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14-145-005
qz = 0.00256 Kz Kzt Kd (1) V^2 H <15 „_0” EXPOSURE --C 1= 1.00 V=175 MPH Kz= 0.85 qz = 0.00256 (0.85) (1.0) (.85) (1.0) (175)'2 Kzt= 1.00 qz = 56.6 PSF Kd=0.85 P= qz (Gcp =/— Gcpi) t. .04/01/14 ............ R -cc z........... .............. ....... .... E- ........ .. .... .... NORTH E WEST ELEVATION 1/4° T.T.BM. IT= co FIN. FL TWO COAT STUCCO TO MATCH EXIST NEW ASPHALT SHINGLE ROOF ZONE 4 + 46.41 PSF — 52.07 PSF �040��=��M'MLVW MVE OFM Oil kv Amim ... . ..... m